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Результаты расчета к примеру 5.1


z, м fi, кПа hi, м
z1 = 2,8 f1 = 46,8 h1 = 1,4
z2 = 4,25 f2 = 53,75 h2 = 1,5
z3 = 5,75 f3 = 57,5 h3 = 1,5
z4 = 7,5 f4 = 42,312 h4 = 2,0
z5 = 9,5 f5 = 44,231 h5 = 2,0
z6 = 11,25 f6 = 53,9775 h6 = 1,5
z7 = 13,0 f7 = 55,969 h7 = 2,0
z8 = 15,0 f8 = 58,245 h8 = 2,0
z9 = 17,0 f9 = 60,521 h9 = 2,0
z10 = 18,65 f10 = 62,3987 h10 = 1,3

Fd = 1×{1×5054,43×0,16 + 1,6 × [1×(46,8 ×1,4 + 53,75×1,5 + 57,5 ×1,5 м + 42,312 ×2,0 + + 44,231 × 2,0 + 53,9775 × 1,5 + 55,969 × 2,0 + 58,245 × 2,0 + 60,521×2,0 + 62,3987 × ×1,3)]} = 2276 кН.







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