It is huge.
How many 4kb pages are being used in the above process?
14 MB / 4 Kb = 14 * 2^20 / 4 * 2^10 = 3.5 * 2 ^10 (approx 4*2^10 = 4MB)
What does that say about most of the 220 page table entries for this process?
They will be empty.
It is huge.
How many 4kb pages are being used in the above process?
14 MB / 4 Kb = 14 * 2^20 / 4 * 2^10 = 3.5 * 2 ^10 (approx 4*2^10 = 4MB)
What does that say about most of the 220 page table entries for this process?
They will be empty.
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