2015-08-21
347
Calculate the total capacity of a NVR requires according to the recording requirementЈЁrecording type, recording file storage timeЈ©. Calculation methodЈє
Step 1ЈєCalculate the storage capacity 
of a channel requires per hour according to the formula(1), Unit: MByte.
= 
ЎВ 8 ЎБ 3600 ЎВ 1024ЈЁ1Ј©
| Bit Stream Size | The Recording File Size in One Hour | The Recording File Size in One Day |
| 256K | 112M | 2.6G |
| 320K | 140M | 3.3G |
| 512K | 225M | 5.3G |
| 768K | 337M | 7.9G |
| 1.00M | 439M | 10.3G |
| 1.50M | 659M | 15.4G |
| 2.00M | 878M | 20.6G |
Ј bit rateЈUnit Kbit/s
The following table shows the recording file size of the common bit rate under constant bit rate within one hour and one day for one channel.
The second step: after confirming the time requirement of
recording, calculate the storage capacity i m one channel requires according to formula(2), unit: MByte.
= ЎБ 
ЎБ 
ЈЁ2Ј©
Ј recording time of each dayЈЁHourЈ©
Ј number of days of recording storage
For example: the HDD capacity for recording one month for 1 channel 1.50M bit stream. Unit GB.
= 659ЎБ24ЎБ31=490296MB= 478GB
The third step: the total capacity (accumulating) qT for 16 channels timing recording for a whole day. Unit: GB
= 
= ЎБ16 =7648GB
If select 500G HDD, 16 pieces of HDD will be required to full record. User selects appropriate HDD according to the capacity.
The fourth step: calculate the total capacity(accumulating) needed for allchannels alarm recording(including motion detection). Unit: GB
ЎБ a%
a% Јalarm occurring rate.
Alarm occurring rate: 
+ 
+ 
+ЎЎ 
)/n 
(n=1Ј2Ј3Ў)
Ј The alarm time of the Nth day(the time difference of larm end and alarm start) Unit: h Ј 24h
Ј the needed HDD capacity of T channels timing
|
|
|
For example: if the alarm occurring rate a% for a month is 50%, then the alarm recording capacity of 16 channels in one month is: Unit:GB
ЎБ a% = ЎБ50 % =7648ЎБ50 % =3.7GB
